![]() Torque and Rotational Equilibrium DIY First-Year Physics Laboratory This work is licensed under the Creative Commons License. In this lab you will be balancing a meter stick on a support stand while a mass (or masses) areĠ6 Lab 6 Torque and Rotational Equilibrium DIY ![]() LAB #6: TORQUE AND MECHANICAL EQUILIBRIUM - LAB #6: TORQUE AND MECHANICAL EQUILIBRIUM OBJECTIVES. CW Torque In Nm Calculated distance from CM of right mass % difference between calculated distance and ģ44 Physics Rotational Equilibrium Lab and Reportģ44 Physics Rotational Equilibrium Lab and Report Name. Lab VII- 7 PHYSICS 1101 LABORATORY REPORT Laboratory VII Name and ID#: Date performed: Day/Time section meets: Lab. LABORATORY VII TORQUE AND EQUILIBRIUM - Home Page - Physics. Of this lab is to determine if the rotational equilibrium condition, u03a3u03c4 = 0. Some sources of error that may occur during the experiment is that the center of balance may be off and it will ruin the data collected.U03a3F = 0 and u03a3u03c4 = 0 - Austin Community College - Start Here. Calculated the torques and set then up to 0 since the system is at equilibrium.Īll the percent errors that we calculated were really small meaning that our calculations were accurate. Then we placed a third wight on one end and we did the same. The percent error that we obtained was only a 0.1%. This point was located at 0.4m and 0.3 m from the center. After we had to place two weights on opposite ends until we found the new balance point. The first part we just had to balance the meter stick in the center. The lab is a helpful way in learning how to calculate torque using the center of balace of the meter stick as an example.There were different cases in calculating the net torque. The 100 g at the 30 cm mark and balancing this system. Stick be to balance this system? Check your result by actually placing Where should the point of support on the meter With the 200 grams still at 90 cm mark, imagine that you now positionĪn additional 100 grams mass at the 30 cm mark on the meter stick.Ĭalculate the position of the center of gravity of this combination (two Remember that the torques in the system are equal. The meter stick be included as part of the mass of the meter stick? The meter stick mass obtained from the balance. Information, calculate the mass of the meter stick. System by changing the balance point of the meter stick. Place about 200 grams at 90 cm on the meter stick and balance the In this step we are solving for the unknown mass of weight 2. Measure the mass of the unknown on a balance andĬompare the two masses by finding the percent difference. Using the equilibrium condition for rotational motion, calculate Positions of the masses until equilibrium is achieved, recording all ![]() Replace one of the above masses with an unknown mass. (length 2)(weight 2) - (length 1)(weight 1) - (length 3)(weight 3) = 0 N m Torque on this system about the point support and compare with theĭiagram shows the distance between the center to the weights. Same side of the support and balance the system with a third mass on the Place the same two masses used above at different locations on the (length 1)(weight 1) - (length 2)(weight 2) = 0 N m
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